140032413431311 has 4 divisors (see below), whose sum is σ = 141135030860032. Its totient is φ = 138929796002592.

The previous prime is 140032413431269. The next prime is 140032413431333. The reversal of 140032413431311 is 113134314230041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140032413431311 - 2⁴⁵ = 104848041342479 is a prime.

It is a super-2 number, since 2×140032413431311² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140032413431111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 551308714170 + ... + 551308714423.

It is an arithmetic number, because the mean of its divisors is an integer number (35283757715008).

Almost surely, 2^{140032413431311} is an apocalyptic number.

140032413431311 is a deficient number, since it is larger than the sum of its proper divisors (1102617428721).

140032413431311 is a wasteful number, since it uses less digits than its factorization.

140032413431311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1102617428720.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 140032413431311 its reverse (113134314230041), we get a palindrome (253166727661352).

The spelling of 140032413431311 in words is "one hundred forty trillion, thirty-two billion, four hundred thirteen million, four hundred thirty-one thousand, three hundred eleven".