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140033114121293 is a prime number
BaseRepresentation
bin11111110101110000000000…
…000001100010010001001101
3200100211000221111022012021222
4133311300000001202101031
5121323300304203340133
61213454154033333125
741332026052465541
oct3765600001422115
9610730844265258
10140033114121293
114068978a2a1738
12138574327071a5
13601a0b2006203
1426818d3167a21
15112c8b16ece98
hex7f5c0006244d

140033114121293 has 2 divisors, whose sum is σ = 140033114121294. Its totient is φ = 140033114121292.

The previous prime is 140033114121209. The next prime is 140033114121343. The reversal of 140033114121293 is 392121411330041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 79412283581449 + 60620830539844 = 8911357^2 + 7785938^2 .

It is a cyclic number.

It is not a de Polignac number, because 140033114121293 - 220 = 140033113072717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140033114121893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016557060646 + 70016557060647.

It is an arithmetic number, because the mean of its divisors is an integer number (70016557060647).

Almost surely, 2140033114121293 is an apocalyptic number.

It is an amenable number.

140033114121293 is a deficient number, since it is larger than the sum of its proper divisors (1).

140033114121293 is an equidigital number, since it uses as much as digits as its factorization.

140033114121293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 140033114121293 in words is "one hundred forty trillion, thirty-three billion, one hundred fourteen million, one hundred twenty-one thousand, two hundred ninety-three".