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140033131210913 is a prime number
BaseRepresentation
bin11111110101110000000001…
…000010101110100010100001
3200100211000222200110102211212
4133311300001002232202201
5121323300323042222123
61213454155443515505
741332026350653523
oct3765600102564241
9610730880412755
10140033131210913
1140689798a04396
1213857438388b95
13601a0b570aa05
1426818d5535a13
15112c8b2e76878
hex7f5c010ae8a1

140033131210913 has 2 divisors, whose sum is σ = 140033131210914. Its totient is φ = 140033131210912.

The previous prime is 140033131210877. The next prime is 140033131211047. The reversal of 140033131210913 is 319012131330041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76124106857569 + 63909024353344 = 8724913^2 + 7994312^2 .

It is a cyclic number.

It is not a de Polignac number, because 140033131210913 - 218 = 140033130948769 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 140033131210913.

It is not a weakly prime, because it can be changed into another prime (140033131210213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016565605456 + 70016565605457.

It is an arithmetic number, because the mean of its divisors is an integer number (70016565605457).

Almost surely, 2140033131210913 is an apocalyptic number.

It is an amenable number.

140033131210913 is a deficient number, since it is larger than the sum of its proper divisors (1).

140033131210913 is an equidigital number, since it uses as much as digits as its factorization.

140033131210913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 32.

Adding to 140033131210913 its reverse (319012131330041), we get a palindrome (459045262540954).

The spelling of 140033131210913 in words is "one hundred forty trillion, thirty-three billion, one hundred thirty-one million, two hundred ten thousand, nine hundred thirteen".