140033131211047 has 2 divisors, whose sum is σ = 140033131211048. Its totient is φ = 140033131211046.

The previous prime is 140033131210913. The next prime is 140033131211063. The reversal of 140033131211047 is 740112131330041.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140033131211047 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140033138211047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016565605523 + 70016565605524.

It is an arithmetic number, because the mean of its divisors is an integer number (70016565605524).

Almost surely, 2^{140033131211047} is an apocalyptic number.

140033131211047 is a deficient number, since it is larger than the sum of its proper divisors (1).

140033131211047 is an equidigital number, since it uses as much as digits as its factorization.

140033131211047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 140033131211047 its reverse (740112131330041), we get a palindrome (880145262541088).

The spelling of 140033131211047 in words is "one hundred forty trillion, thirty-three billion, one hundred thirty-one million, two hundred eleven thousand, forty-seven".