Base | Representation |
---|---|
bin | 11111110101110000000110… |
… | …000010100011000110011111 |
3 | 200100211001012112012220122112 |
4 | 133311300012002203012133 |
5 | 121323301011023101033 |
6 | 1213454212040504235 |
7 | 41332031416410002 |
oct | 3765600602430637 |
9 | 610731175186575 |
10 | 140033215050143 |
11 | 40689831268008 |
12 | 1385746047b07b |
13 | 601a0c9bb371c |
14 | 268190271b539 |
15 | 112c8ba4d7c48 |
hex | 7f5c060a319f |
140033215050143 has 2 divisors, whose sum is σ = 140033215050144. Its totient is φ = 140033215050142.
The previous prime is 140033215050109. The next prime is 140033215050149. The reversal of 140033215050143 is 341050512330041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 140033215050143 - 220 = 140033214001567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (140033215050149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70016607525071 + 70016607525072.
It is an arithmetic number, because the mean of its divisors is an integer number (70016607525072).
Almost surely, 2140033215050143 is an apocalyptic number.
140033215050143 is a deficient number, since it is larger than the sum of its proper divisors (1).
140033215050143 is an equidigital number, since it uses as much as digits as its factorization.
140033215050143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 140033215050143 its reverse (341050512330041), we get a palindrome (481083727380184).
The spelling of 140033215050143 in words is "one hundred forty trillion, thirty-three billion, two hundred fifteen million, fifty thousand, one hundred forty-three".
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