Base | Representation |
---|---|
bin | 1000001001101010100… |
… | …0110101110110111111 |
3 | 111101110011110021212020 |
4 | 2002122220311312333 |
5 | 4243242014213403 |
6 | 144155212411223 |
7 | 13055104562562 |
oct | 2023250656677 |
9 | 441404407766 |
10 | 140033351103 |
11 | 5442a1a3338 |
12 | 23180a76b13 |
13 | 1028876b389 |
14 | 6ac5c304d9 |
15 | 3998b0d453 |
hex | 209aa35dbf |
140033351103 has 4 divisors (see below), whose sum is σ = 186711134808. Its totient is φ = 93355567400.
The previous prime is 140033351077. The next prime is 140033351119. The reversal of 140033351103 is 301153330041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301153330041 = 3 ⋅100384443347.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-140033351103 is a prime.
It is a super-2 number, since 2×1400333511032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140033351603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23338891848 + ... + 23338891853.
It is an arithmetic number, because the mean of its divisors is an integer number (46677783702).
Almost surely, 2140033351103 is an apocalyptic number.
140033351103 is a deficient number, since it is larger than the sum of its proper divisors (46677783705).
140033351103 is an equidigital number, since it uses as much as digits as its factorization.
140033351103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46677783704.
The product of its (nonzero) digits is 1620, while the sum is 24.
Adding to 140033351103 its reverse (301153330041), we get a palindrome (441186681144).
The spelling of 140033351103 in words is "one hundred forty billion, thirty-three million, three hundred fifty-one thousand, one hundred three".
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