Search a number
-
+
1400344003481 is a prime number
BaseRepresentation
bin10100011000001011000…
…000011100001110011001
311221212112101021222112112
4110120023000130032121
5140420401031102411
62551150435522105
7203112554430443
oct24301300341631
94855471258475
101400344003481
1149a978757195
121a7490459335
13a2089c70827
144bac4195493
152665d461b8b
hex1460b01c399

1400344003481 has 2 divisors, whose sum is σ = 1400344003482. Its totient is φ = 1400344003480.

The previous prime is 1400344003423. The next prime is 1400344003483. The reversal of 1400344003481 is 1843004430041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1299611400025 + 100732603456 = 1140005^2 + 317384^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400344003481 - 238 = 1125466096537 is a prime.

It is a super-2 number, since 2×14003440034812 (a number of 25 digits) contains 22 as substring.

Together with 1400344003483, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1400344003483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700172001740 + 700172001741.

It is an arithmetic number, because the mean of its divisors is an integer number (700172001741).

Almost surely, 21400344003481 is an apocalyptic number.

It is an amenable number.

1400344003481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400344003481 is an equidigital number, since it uses as much as digits as its factorization.

1400344003481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18432, while the sum is 32.

The spelling of 1400344003481 in words is "one trillion, four hundred billion, three hundred forty-four million, three thousand, four hundred eighty-one".