Base | Representation |
---|---|
bin | 10100011000001011000… |
… | …000111011101000001111 |
3 | 11221212112101112111222121 |
4 | 110120023000323220033 |
5 | 140420401044211421 |
6 | 2551150442353411 |
7 | 203112555504451 |
oct | 24301300735017 |
9 | 4855471474877 |
10 | 1400344132111 |
11 | 49a9788348a1 |
12 | 1a74904bb867 |
13 | a2089cb7242 |
14 | 4bac41ca2d1 |
15 | 2665d489d41 |
hex | 1460b03ba0f |
1400344132111 has 2 divisors, whose sum is σ = 1400344132112. Its totient is φ = 1400344132110.
The previous prime is 1400344132081. The next prime is 1400344132169. The reversal of 1400344132111 is 1112314430041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1400344132111 - 27 = 1400344131983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400344132181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700172066055 + 700172066056.
It is an arithmetic number, because the mean of its divisors is an integer number (700172066056).
Almost surely, 21400344132111 is an apocalyptic number.
1400344132111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400344132111 is an equidigital number, since it uses as much as digits as its factorization.
1400344132111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1400344132111 its reverse (1112314430041), we get a palindrome (2512658562152).
The spelling of 1400344132111 in words is "one trillion, four hundred billion, three hundred forty-four million, one hundred thirty-two thousand, one hundred eleven".
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