1400400121433 has 8 divisors (see below), whose sum is σ = 1401698427360. Its totient is φ = 1399102282080.

The previous prime is 1400400121399. The next prime is 1400400121451. The reversal of 1400400121433 is 3341210040041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1400400121433 - 2¹⁰ = 1400400120409 is a prime.

It is a super-2 number, since 2×1400400121433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1400400121399 and 1400400121408.

It is not an unprimeable number, because it can be changed into a prime (1400400127433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6038798 + ... + 6266408.

It is an arithmetic number, because the mean of its divisors is an integer number (175212303420).

Almost surely, 2^{1400400121433} is an apocalyptic number.

It is an amenable number.

1400400121433 is a deficient number, since it is larger than the sum of its proper divisors (1298305927).

1400400121433 is a wasteful number, since it uses less digits than its factorization.

1400400121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233287.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1400400121433 its reverse (3341210040041), we get a palindrome (4741610161474).

The spelling of 1400400121433 in words is "one trillion, four hundred billion, four hundred million, one hundred twenty-one thousand, four hundred thirty-three".