14004013000330 has 8 divisors (see below), whose sum is σ = 25207223400612. Its totient is φ = 5601605200128.

The previous prime is 14004013000279. The next prime is 14004013000343. The reversal of 14004013000330 is 3300031040041.

It can be written as a sum of positive squares in 2 ways, for example, as 13765977324009 + 238035676321 = 3710253^2 + 487889^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×14004013000330² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14004013000298 and 14004013000307.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 700200650007 + ... + 700200650026.

Almost surely, 2^{14004013000330} is an apocalyptic number.

14004013000330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14004013000330 is a deficient number, since it is larger than the sum of its proper divisors (11203210400282).

14004013000330 is a wasteful number, since it uses less digits than its factorization.

14004013000330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1400401300040.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 14004013000330 its reverse (3300031040041), we get a palindrome (17304044040371).

The spelling of 14004013000330 in words is "fourteen trillion, four billion, thirteen million, three hundred thirty", and thus it is an aban number.