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14004013223201 is a prime number
BaseRepresentation
bin1100101111001001000000…
…1110111100110100100001
31211120202210202111211000212
43023302100032330310201
53313420204341120301
645441204352223505
72643520334236541
oct313622016746441
954522722454025
1014004013223201
11450a083420681
1216a20a383ab95
137a775a525331
14365b25465321
151944233d64bb
hexcbc903bcd21

14004013223201 has 2 divisors, whose sum is σ = 14004013223202. Its totient is φ = 14004013223200.

The previous prime is 14004013223107. The next prime is 14004013223231. The reversal of 14004013223201 is 10232231040041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8810062830625 + 5193950392576 = 2968175^2 + 2279024^2 .

It is a cyclic number.

It is not a de Polignac number, because 14004013223201 - 226 = 14003946114337 is a prime.

It is a super-2 number, since 2×140040132232012 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14004013223231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002006611600 + 7002006611601.

It is an arithmetic number, because the mean of its divisors is an integer number (7002006611601).

Almost surely, 214004013223201 is an apocalyptic number.

It is an amenable number.

14004013223201 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004013223201 is an equidigital number, since it uses as much as digits as its factorization.

14004013223201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14004013223201 its reverse (10232231040041), we get a palindrome (24236244263242).

The spelling of 14004013223201 in words is "fourteen trillion, four billion, thirteen million, two hundred twenty-three thousand, two hundred one".