Base | Representation |
---|---|
bin | 1100101111001001001001… |
… | …1100001000000000110000 |
3 | 1211120202220100011000122211 |
4 | 3023302102130020000300 |
5 | 3313420243324400334 |
6 | 45441212153341504 |
7 | 2643521263634155 |
oct | 313622234100060 |
9 | 54522810130584 |
10 | 14004050231344 |
11 | 450a0a22a8418 |
12 | 16a20b4107894 |
13 | 7a77650b2144 |
14 | 365b2a33a22c |
15 | 194426796a64 |
hex | cbc92708030 |
14004050231344 has 10 divisors (see below), whose sum is σ = 27132847323260. Its totient is φ = 7002025115664.
The previous prime is 14004050231317. The next prime is 14004050231357. The reversal of 14004050231344 is 44313205040041.
It is a super-2 number, since 2×140040502313442 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 437626569714 + ... + 437626569745.
It is an arithmetic number, because the mean of its divisors is an integer number (2713284732326).
Almost surely, 214004050231344 is an apocalyptic number.
It is an amenable number.
14004050231344 is a deficient number, since it is larger than the sum of its proper divisors (13128797091916).
14004050231344 is an equidigital number, since it uses as much as digits as its factorization.
14004050231344 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 875253139467 (or 875253139461 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 14004050231344 its reverse (44313205040041), we get a palindrome (58317255271385).
The spelling of 14004050231344 in words is "fourteen trillion, four billion, fifty million, two hundred thirty-one thousand, three hundred forty-four".
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