Search a number
-
+
140042214344302 = 270021107172151
BaseRepresentation
bin11111110101111000011110…
…011100001000011001101110
3200100211220102200222102102121
4133311320132130020121232
5121323422423333004202
61213502301034543154
741332500423221134
oct3765703634103156
9610756380872377
10140042214344302
114069262a1169a6
1213859152297aba
13601ac0247765a
1426821179cb754
15112cc455c5537
hex7f5e1e70866e

140042214344302 has 4 divisors (see below), whose sum is σ = 210063321516456. Its totient is φ = 70021107172150.

The previous prime is 140042214344293. The next prime is 140042214344309. The reversal of 140042214344302 is 203443412240041.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1400422143443022 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140042214344309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35010553586074 + ... + 35010553586077.

It is an arithmetic number, because the mean of its divisors is an integer number (52515830379114).

Almost surely, 2140042214344302 is an apocalyptic number.

140042214344302 is a deficient number, since it is larger than the sum of its proper divisors (70021107172154).

140042214344302 is an equidigital number, since it uses as much as digits as its factorization.

140042214344302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70021107172153.

The product of its (nonzero) digits is 73728, while the sum is 34.

Adding to 140042214344302 its reverse (203443412240041), we get a palindrome (343485626584343).

The spelling of 140042214344302 in words is "one hundred forty trillion, forty-two billion, two hundred fourteen million, three hundred forty-four thousand, three hundred two".

Divisors: 1 2 70021107172151 140042214344302