1400423331013 has 4 divisors (see below), whose sum is σ = 1600483806880. Its totient is φ = 1200362855148.

The previous prime is 1400423331011. The next prime is 1400423331067. The reversal of 1400423331013 is 3101333240041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1400423331013 - 2¹ = 1400423331011 is a prime.

It is a super-2 number, since 2×1400423331013² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400423331011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100030237923 + ... + 100030237936.

It is an arithmetic number, because the mean of its divisors is an integer number (400120951720).

Almost surely, 2^{1400423331013} is an apocalyptic number.

It is an amenable number.

1400423331013 is a deficient number, since it is larger than the sum of its proper divisors (200060475867).

1400423331013 is an equidigital number, since it uses as much as digits as its factorization.

1400423331013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200060475866.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1400423331013 its reverse (3101333240041), we get a palindrome (4501756571054).

The spelling of 1400423331013 in words is "one trillion, four hundred billion, four hundred twenty-three million, three hundred thirty-one thousand, thirteen".