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14004311441 is a prime number
BaseRepresentation
bin11010000101011100…
…01101010110010001
31100010222120201202112
431002232031112101
5212140100431231
610233344555105
71004016453221
oct150256152621
940128521675
1014004311441
115a3708350a
12286a022a95
13142248b423
1496bcba081
1556e6d592b
hex342b8d591

14004311441 has 2 divisors, whose sum is σ = 14004311442. Its totient is φ = 14004311440.

The previous prime is 14004311429. The next prime is 14004311491. The reversal of 14004311441 is 14411340041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12529444225 + 1474867216 = 111935^2 + 38404^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14004311441 is a prime.

It is a super-2 number, since 2×140043114412 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14004311401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7002155720 + 7002155721.

It is an arithmetic number, because the mean of its divisors is an integer number (7002155721).

Almost surely, 214004311441 is an apocalyptic number.

It is an amenable number.

14004311441 is a deficient number, since it is larger than the sum of its proper divisors (1).

14004311441 is an equidigital number, since it uses as much as digits as its factorization.

14004311441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14004311441 its reverse (14411340041), we get a palindrome (28415651482).

The spelling of 14004311441 in words is "fourteen billion, four million, three hundred eleven thousand, four hundred forty-one".