140043300412277 has 2 divisors, whose sum is σ = 140043300412278. Its totient is φ = 140043300412276.

The previous prime is 140043300412273. The next prime is 140043300412297. The reversal of 140043300412277 is 772214003340041.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 140008553215441 + 34747196836 = 11832521^2 + 186406^2 .

It is a cyclic number.

It is not a de Polignac number, because 140043300412277 - 2² = 140043300412273 is a prime.

It is a super-2 number, since 2×140043300412277² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140043300412277.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140043300412273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70021650206138 + 70021650206139.

It is an arithmetic number, because the mean of its divisors is an integer number (70021650206139).

Almost surely, 2^{140043300412277} is an apocalyptic number.

It is an amenable number.

140043300412277 is a deficient number, since it is larger than the sum of its proper divisors (1).

140043300412277 is an equidigital number, since it uses as much as digits as its factorization.

140043300412277 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112896, while the sum is 38.

The spelling of 140043300412277 in words is "one hundred forty trillion, forty-three billion, three hundred million, four hundred twelve thousand, two hundred seventy-seven".