1400434121221 has 4 divisors (see below), whose sum is σ = 1400564150944. Its totient is φ = 1400304091500.

The previous prime is 1400434121197. The next prime is 1400434121321. The reversal of 1400434121221 is 1221214340041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1400434121221 is a prime.

It is a super-2 number, since 2×1400434121221² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1400434121321) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64998705 + ... + 65020246.

It is an arithmetic number, because the mean of its divisors is an integer number (350141037736).

Almost surely, 2^{1400434121221} is an apocalyptic number.

It is an amenable number.

1400434121221 is a deficient number, since it is larger than the sum of its proper divisors (130029723).

1400434121221 is a wasteful number, since it uses less digits than its factorization.

1400434121221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 130029722.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1400434121221 its reverse (1221214340041), we get a palindrome (2621648461262).

The spelling of 1400434121221 in words is "one trillion, four hundred billion, four hundred thirty-four million, one hundred twenty-one thousand, two hundred twenty-one".