Base | Representation |
---|---|
bin | 10100011000010000110… |
… | …000001111101010110111 |
3 | 11221212210002201111120111 |
4 | 110120100300033222313 |
5 | 140421100221433142 |
6 | 2551204202243451 |
7 | 203115135112303 |
oct | 24302060175267 |
9 | 4855702644514 |
10 | 1400440421047 |
11 | 49aa18121128 |
12 | 1a74b87b6587 |
13 | a20a3c2b845 |
14 | 4bad2cd2d03 |
15 | 26666b59e17 |
hex | 14610c0fab7 |
1400440421047 has 2 divisors, whose sum is σ = 1400440421048. Its totient is φ = 1400440421046.
The previous prime is 1400440420949. The next prime is 1400440421053. The reversal of 1400440421047 is 7401240440041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1400440421047 - 231 = 1398292937399 is a prime.
It is a super-2 number, since 2×14004404210472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1400440461047) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700220210523 + 700220210524.
It is an arithmetic number, because the mean of its divisors is an integer number (700220210524).
Almost surely, 21400440421047 is an apocalyptic number.
1400440421047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400440421047 is an equidigital number, since it uses as much as digits as its factorization.
1400440421047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14336, while the sum is 31.
Adding to 1400440421047 its reverse (7401240440041), we get a palindrome (8801680861088).
The spelling of 1400440421047 in words is "one trillion, four hundred billion, four hundred forty million, four hundred twenty-one thousand, forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •