Base | Representation |
---|---|
bin | 10100011000010000110… |
… | …000001111111000100011 |
3 | 11221212210002201112202221 |
4 | 110120100300033320203 |
5 | 140421100222000143 |
6 | 2551204202251511 |
7 | 203115135114664 |
oct | 24302060177043 |
9 | 4855702645687 |
10 | 1400440421923 |
11 | 49aa18121854 |
12 | 1a74b87b6b97 |
13 | a20a3c2c06a |
14 | 4bad2cd336b |
15 | 26666b5a2ed |
hex | 14610c0fe23 |
1400440421923 has 2 divisors, whose sum is σ = 1400440421924. Its totient is φ = 1400440421922.
The previous prime is 1400440421903. The next prime is 1400440421927. The reversal of 1400440421923 is 3291240440041.
It is a strong prime.
It is an emirp because it is prime and its reverse (3291240440041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1400440421923 - 213 = 1400440413731 is a prime.
It is a super-2 number, since 2×14004404219232 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1400440421927) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700220210961 + 700220210962.
It is an arithmetic number, because the mean of its divisors is an integer number (700220210962).
Almost surely, 21400440421923 is an apocalyptic number.
1400440421923 is a deficient number, since it is larger than the sum of its proper divisors (1).
1400440421923 is an equidigital number, since it uses as much as digits as its factorization.
1400440421923 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 27648, while the sum is 34.
Adding to 1400440421923 its reverse (3291240440041), we get a palindrome (4691680861964).
The spelling of 1400440421923 in words is "one trillion, four hundred billion, four hundred forty million, four hundred twenty-one thousand, nine hundred twenty-three".
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