Base | Representation |
---|---|
bin | 1000001001101101001… |
… | …0010100111001000011 |
3 | 111101110220220210120110 |
4 | 2002123102110321003 |
5 | 4243302310213430 |
6 | 144200241442403 |
7 | 13055266165263 |
oct | 2023322247103 |
9 | 441426823513 |
10 | 140044226115 |
11 | 54435350952 |
12 | 23184640403 |
13 | 1028aaa82b1 |
14 | 6ac74617a3 |
15 | 3999a5a7b0 |
hex | 209b494e43 |
140044226115 has 32 divisors (see below), whose sum is σ = 225781992000. Its totient is φ = 74120768000.
The previous prime is 140044226099. The next prime is 140044226123. The reversal of 140044226115 is 511622440041.
It is not a de Polignac number, because 140044226115 - 24 = 140044226099 is a prime.
It is a super-2 number, since 2×1400442261152 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2450365 + ... + 2506865.
It is an arithmetic number, because the mean of its divisors is an integer number (7055687250).
Almost surely, 2140044226115 is an apocalyptic number.
140044226115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
140044226115 is a deficient number, since it is larger than the sum of its proper divisors (85737765885).
140044226115 is a wasteful number, since it uses less digits than its factorization.
140044226115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57767.
The product of its (nonzero) digits is 7680, while the sum is 30.
Adding to 140044226115 its reverse (511622440041), we get a palindrome (651666666156).
The spelling of 140044226115 in words is "one hundred forty billion, forty-four million, two hundred twenty-six thousand, one hundred fifteen".
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