Base | Representation |
---|---|
bin | 11010000101100001… |
… | …11101110010011111 |
3 | 1100011000221110010021 |
4 | 31002300331302133 |
5 | 212140242043033 |
6 | 10233412253011 |
7 | 1004025553222 |
oct | 150260756237 |
9 | 40130843107 |
10 | 14005034143 |
11 | 5a37527491 |
12 | 286a311167 |
13 | 1422682369 |
14 | 96c0275b9 |
15 | 56e7c9b2d |
hex | 342c3dc9f |
14005034143 has 4 divisors (see below), whose sum is σ = 14006133288. Its totient is φ = 14003935000.
The previous prime is 14005034137. The next prime is 14005034161. The reversal of 14005034143 is 34143050041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14005034143 - 29 = 14005033631 is a prime.
It is a super-2 number, since 2×140050341432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14005034543) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 530233 + ... + 556018.
It is an arithmetic number, because the mean of its divisors is an integer number (3501533322).
Almost surely, 214005034143 is an apocalyptic number.
14005034143 is a deficient number, since it is larger than the sum of its proper divisors (1099145).
14005034143 is a wasteful number, since it uses less digits than its factorization.
14005034143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1099144.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14005034143 its reverse (34143050041), we get a palindrome (48148084184).
The spelling of 14005034143 in words is "fourteen billion, five million, thirty-four thousand, one hundred forty-three".
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