140052040333 has 2 divisors, whose sum is σ = 140052040334. Its totient is φ = 140052040332.

The previous prime is 140052040319. The next prime is 140052040339. The reversal of 140052040333 is 333040250041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 136469658724 + 3582381609 = 369418^2 + 59853^2 .

It is an emirp because it is prime and its reverse (333040250041) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140052040333 is a prime.

It is a super-2 number, since 2×140052040333² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 140052040298 and 140052040307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140052040339) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70026020166 + 70026020167.

It is an arithmetic number, because the mean of its divisors is an integer number (70026020167).

Almost surely, 2^140052040333 is an apocalyptic number.

It is an amenable number.

140052040333 is a deficient number, since it is larger than the sum of its proper divisors (1).

140052040333 is an equidigital number, since it uses as much as digits as its factorization.

140052040333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 140052040333 its reverse (333040250041), we get a palindrome (473092290374).

The spelling of 140052040333 in words is "one hundred forty billion, fifty-two million, forty thousand, three hundred thirty-three".