140053241411 has 2 divisors, whose sum is σ = 140053241412. Its totient is φ = 140053241410.

The previous prime is 140053241381. The next prime is 140053241413. The reversal of 140053241411 is 114142350041.

140053241411 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (114142350041) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 140053241411 - 2¹⁰ = 140053240387 is a prime.

It is a super-2 number, since 2×140053241411² (a number of 23 digits) contains 22 as substring.

Together with 140053241413, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (140053241413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70026620705 + 70026620706.

It is an arithmetic number, because the mean of its divisors is an integer number (70026620706).

Almost surely, 2^140053241411 is an apocalyptic number.

140053241411 is a deficient number, since it is larger than the sum of its proper divisors (1).

140053241411 is an equidigital number, since it uses as much as digits as its factorization.

140053241411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1920, while the sum is 26.

Adding to 140053241411 its reverse (114142350041), we get a palindrome (254195591452).

The spelling of 140053241411 in words is "one hundred forty billion, fifty-three million, two hundred forty-one thousand, four hundred eleven".