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14007333481 = 17823960793
BaseRepresentation
bin11010000101110011…
…01111001001101001
31100011012021021012221
431002321233021221
5212141334132411
610233533434041
71004054240641
oct150271571151
940135237187
1014007333481
115a38857a69
12286b03b921
131422ca8b0b
1496c465521
1556ead1071
hex342e6f269

14007333481 has 4 divisors (see below), whose sum is σ = 14831294292. Its totient is φ = 13183372672.

The previous prime is 14007333469. The next prime is 14007333491. The reversal of 14007333481 is 18433370041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4648512400 + 9358821081 = 68180^2 + 96741^2 .

It is a cyclic number.

It is not a de Polignac number, because 14007333481 - 225 = 13973779049 is a prime.

It is a super-3 number, since 3×140073334813 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (14007333421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 411980380 + ... + 411980413.

It is an arithmetic number, because the mean of its divisors is an integer number (3707823573).

Almost surely, 214007333481 is an apocalyptic number.

It is an amenable number.

14007333481 is a deficient number, since it is larger than the sum of its proper divisors (823960811).

14007333481 is an equidigital number, since it uses as much as digits as its factorization.

14007333481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 823960810.

The product of its (nonzero) digits is 24192, while the sum is 34.

The spelling of 14007333481 in words is "fourteen billion, seven million, three hundred thirty-three thousand, four hundred eighty-one".

Divisors: 1 17 823960793 14007333481