14010010410113 has 4 divisors (see below), whose sum is σ = 14013862492500. Its totient is φ = 14006158327728.

The previous prime is 14010010410101. The next prime is 14010010410119. The reversal of 14010010410113 is 31101401001041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2841962099344 + 11168048310769 = 1685812^2 + 3341863^2 .

It is a cyclic number.

It is not a de Polignac number, because 14010010410113 - 2¹⁰ = 14010010409089 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14010010410091 and 14010010410100.

It is not an unprimeable number, because it can be changed into a prime (14010010410119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1926035738 + ... + 1926043011.

It is an arithmetic number, because the mean of its divisors is an integer number (3503465623125).

Almost surely, 2^{14010010410113} is an apocalyptic number.

It is an amenable number.

14010010410113 is a deficient number, since it is larger than the sum of its proper divisors (3852082387).

14010010410113 is an equidigital number, since it uses as much as digits as its factorization.

14010010410113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3852082386.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 14010010410113 its reverse (31101401001041), we get a palindrome (45111411411154).

The spelling of 14010010410113 in words is "fourteen trillion, ten billion, ten million, four hundred ten thousand, one hundred thirteen".