140100113 has 4 divisors (see below), whose sum is σ = 140271168. Its totient is φ = 139929060.

The previous prime is 140100097. The next prime is 140100133. The reversal of 140100113 is 311001041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140100113 - 2⁴ = 140100097 is a prime.

It is a super-2 number, since 2×140100113² = 39256083325225538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140100094 and 140100103.

It is not an unprimeable number, because it can be changed into a prime (140100133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 84293 + ... + 85938.

It is an arithmetic number, because the mean of its divisors is an integer number (35067792).

Almost surely, 2^140100113 is an apocalyptic number.

It is an amenable number.

140100113 is a deficient number, since it is larger than the sum of its proper divisors (171055).

140100113 is an equidigital number, since it uses as much as digits as its factorization.

140100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171054.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 140100113 is about 11836.3893565563. The cubic root of 140100113 is about 519.3731512091.

Adding to 140100113 its reverse (311001041), we get a palindrome (451101154).

The spelling of 140100113 in words is "one hundred forty million, one hundred thousand, one hundred thirteen".