14010122411433 has 12 divisors (see below), whose sum is σ = 20245113577728. Its totient is φ = 9336264640920.

The previous prime is 14010122411431. The next prime is 14010122411443. The reversal of 14010122411433 is 33411422101041.

It is a happy number.

14010122411433 is a `hidden beast` number, since 1 + 4 + 0 + 1 + 0 + 1 + 224 + 1 + 1 + 433 = 666.

It is not a de Polignac number, because 14010122411433 - 2¹ = 14010122411431 is a prime.

It is a super-2 number, since 2×14010122411433² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14010122411397 and 14010122411406.

It is not an unprimeable number, because it can be changed into a prime (14010122411431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 318057313 + ... + 318101358.

It is an arithmetic number, because the mean of its divisors is an integer number (1687092798144).

Almost surely, 2^{14010122411433} is an apocalyptic number.

It is an amenable number.

14010122411433 is a deficient number, since it is larger than the sum of its proper divisors (6234991166295).

14010122411433 is a wasteful number, since it uses less digits than its factorization.

14010122411433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 636161124 (or 636161121 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 14010122411433 its reverse (33411422101041), we get a palindrome (47421544512474).

The spelling of 14010122411433 in words is "fourteen trillion, ten billion, one hundred twenty-two million, four hundred eleven thousand, four hundred thirty-three".