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14010153 = 34670051
BaseRepresentation
bin110101011100…
…011100101001
3222100210022120
4311130130221
512041311103
61220141453
7230040633
oct65343451
928323276
1014010153
1179aa043
124837889
132b96c41
141c09a53
15136b253
hexd5c729

14010153 has 4 divisors (see below), whose sum is σ = 18680208. Its totient is φ = 9340100.

The previous prime is 14010133. The next prime is 14010187. The reversal of 14010153 is 35101041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14010153 - 25 = 14010121 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14010133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335023 + ... + 2335028.

It is an arithmetic number, because the mean of its divisors is an integer number (4670052).

Almost surely, 214010153 is an apocalyptic number.

It is an amenable number.

14010153 is a deficient number, since it is larger than the sum of its proper divisors (4670055).

14010153 is an equidigital number, since it uses as much as digits as its factorization.

14010153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4670054.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 14010153 is about 3743.0138925737. The cubic root of 14010153 is about 241.0724746590.

Adding to 14010153 its reverse (35101041), we get a palindrome (49111194).

The spelling of 14010153 in words is "fourteen million, ten thousand, one hundred fifty-three".

Divisors: 1 3 4670051 14010153