140104117 has 2 divisors, whose sum is σ = 140104118. Its totient is φ = 140104116.

The previous prime is 140104057. The next prime is 140104171. The reversal of 140104117 is 711401041.

140104117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (140104171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112656996 + 27447121 = 10614^2 + 5239^2 .

It is a cyclic number.

It is not a de Polignac number, because 140104117 - 2¹¹ = 140102069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140104094 and 140104103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140134117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70052058 + 70052059.

It is an arithmetic number, because the mean of its divisors is an integer number (70052059).

Almost surely, 2^140104117 is an apocalyptic number.

It is an amenable number.

140104117 is a deficient number, since it is larger than the sum of its proper divisors (1).

140104117 is an equidigital number, since it uses as much as digits as its factorization.

140104117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 19.

The square root of 140104117 is about 11836.5584947653. The cubic root of 140104117 is about 519.3780989812.

Adding to 140104117 its reverse (711401041), we get a palindrome (851505158).

It can be divided in two parts, 14010 and 4117, that multiplied together give a triangular number (57679170 = T₁₀₇₄₀).

The spelling of 140104117 in words is "one hundred forty million, one hundred four thousand, one hundred seventeen".