Base | Representation |
---|---|
bin | 11111110110110011000101… |
… | …110100010001110100010111 |
3 | 200101001220212221022012001020 |
4 | 133312303011310101310113 |
5 | 121330440322403332133 |
6 | 1213551230203332223 |
7 | 41340156163450305 |
oct | 3766630564216427 |
9 | 611056787265036 |
10 | 140105152011543 |
11 | 4070729685a924 |
12 | 13869397b21073 |
13 | 6023b22703384 |
14 | 26851a869d275 |
15 | 112e6caba80b3 |
hex | 7f6cc5d11d17 |
140105152011543 has 4 divisors (see below), whose sum is σ = 186806869348728. Its totient is φ = 93403434674360.
The previous prime is 140105152011533. The next prime is 140105152011563. The reversal of 140105152011543 is 345110251501041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 140105152011543 - 24 = 140105152011527 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (140105152011523) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23350858668588 + ... + 23350858668593.
It is an arithmetic number, because the mean of its divisors is an integer number (46701717337182).
Almost surely, 2140105152011543 is an apocalyptic number.
140105152011543 is a deficient number, since it is larger than the sum of its proper divisors (46701717337185).
140105152011543 is an equidigital number, since it uses as much as digits as its factorization.
140105152011543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46701717337184.
The product of its (nonzero) digits is 12000, while the sum is 33.
The spelling of 140105152011543 in words is "one hundred forty trillion, one hundred five billion, one hundred fifty-two million, eleven thousand, five hundred forty-three".
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