14011001324321 has 2 divisors, whose sum is σ = 14011001324322. Its totient is φ = 14011001324320.

The previous prime is 14011001324267. The next prime is 14011001324357. The reversal of 14011001324321 is 12342310011041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13976045787025 + 34955537296 = 3738455^2 + 186964^2 .

It is a cyclic number.

It is not a de Polignac number, because 14011001324321 - 2²² = 14010997130017 is a prime.

It is a super-2 number, since 2×14011001324321² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14011001324371) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005500662160 + 7005500662161.

It is an arithmetic number, because the mean of its divisors is an integer number (7005500662161).

Almost surely, 2^{14011001324321} is an apocalyptic number.

It is an amenable number.

14011001324321 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011001324321 is an equidigital number, since it uses as much as digits as its factorization.

14011001324321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14011001324321 its reverse (12342310011041), we get a palindrome (26353311335362).

The spelling of 14011001324321 in words is "fourteen trillion, eleven billion, one million, three hundred twenty-four thousand, three hundred twenty-one".