140110041112021 has 4 divisors (see below), whose sum is σ = 142201235755552. Its totient is φ = 138018846468492.

The previous prime is 140110041112007. The next prime is 140110041112039. The reversal of 140110041112021 is 120211140011041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140110041112021 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140110041112021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (140110041112001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1045597321665 + ... + 1045597321798.

It is an arithmetic number, because the mean of its divisors is an integer number (35550308938888).

Almost surely, 2^{140110041112021} is an apocalyptic number.

It is an amenable number.

140110041112021 is a deficient number, since it is larger than the sum of its proper divisors (2091194643531).

140110041112021 is an equidigital number, since it uses as much as digits as its factorization.

140110041112021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2091194643530.

The product of its (nonzero) digits is 64, while the sum is 19.

Adding to 140110041112021 its reverse (120211140011041), we get a palindrome (260321181123062).

The spelling of 140110041112021 in words is "one hundred forty trillion, one hundred ten billion, forty-one million, one hundred twelve thousand, twenty-one".