14011103053 has 4 divisors (see below), whose sum is σ = 14011352608. Its totient is φ = 14010853500.

The previous prime is 14011103011. The next prime is 14011103069. The reversal of 14011103053 is 35030111041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 35030111041 = 7817 ⋅4481273.

It is a cyclic number.

It is not a de Polignac number, because 14011103053 - 2⁹ = 14011102541 is a prime.

It is a super-2 number, since 2×14011103053² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14011103053.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011103003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3178 + ... + 167428.

It is an arithmetic number, because the mean of its divisors is an integer number (3502838152).

Almost surely, 2^14011103053 is an apocalyptic number.

It is an amenable number.

14011103053 is a deficient number, since it is larger than the sum of its proper divisors (249555).

14011103053 is an equidigital number, since it uses as much as digits as its factorization.

14011103053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 249554.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 14011103053 its reverse (35030111041), we get a palindrome (49041214094).

The spelling of 14011103053 in words is "fourteen billion, eleven million, one hundred three thousand, fifty-three".