Search a number
-
+
14011114053 = 34670371351
BaseRepresentation
bin11010000110010000…
…01010001001000101
31100011110101100012010
431003020022021011
5212143321122203
610234150444433
71004131335006
oct150310121105
940143340163
1014011114053
115a3a9aa402
122870363719
131423a00841
1496cb6b1ad
155700cb303
hex34320a245

14011114053 has 4 divisors (see below), whose sum is σ = 18681485408. Its totient is φ = 9340742700.

The previous prime is 14011113997. The next prime is 14011114057. The reversal of 14011114053 is 35041111041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14011114053 - 28 = 14011113797 is a prime.

It is a super-2 number, since 2×140111140532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011114057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335185673 + ... + 2335185678.

It is an arithmetic number, because the mean of its divisors is an integer number (4670371352).

Almost surely, 214011114053 is an apocalyptic number.

It is an amenable number.

14011114053 is a deficient number, since it is larger than the sum of its proper divisors (4670371355).

14011114053 is an equidigital number, since it uses as much as digits as its factorization.

14011114053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4670371354.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 14011114053 its reverse (35041111041), we get a palindrome (49052225094).

The spelling of 14011114053 in words is "fourteen billion, eleven million, one hundred fourteen thousand, fifty-three".

Divisors: 1 3 4670371351 14011114053