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140111214031435 = 5126132221695299
BaseRepresentation
bin11111110110111000101111…
…001001000011001001001011
3200101002111112102001201000111
4133312320233021003021023
5121331040231243001220
61213554111513415151
741340462332664553
oct3766705711031113
9611074472051014
10140111214031435
11407099176a1119
121386a5aa10a4b7
13602457a5a55aa
1426855c1814163
15112e932e9215a
hex7f6e2f24324b

140111214031435 has 8 divisors (see below), whose sum is σ = 168146787085200. Its totient is φ = 112080084393504.

The previous prime is 140111214031423. The next prime is 140111214031457. The reversal of 140111214031435 is 534130412111041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140111214031435 - 29 = 140111214030923 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140111214031397 and 140111214031406.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1110784585 + ... + 1110910714.

It is an arithmetic number, because the mean of its divisors is an integer number (21018348385650).

Almost surely, 2140111214031435 is an apocalyptic number.

140111214031435 is a deficient number, since it is larger than the sum of its proper divisors (28035573053765).

140111214031435 is a wasteful number, since it uses less digits than its factorization.

140111214031435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2221707917.

The product of its (nonzero) digits is 5760, while the sum is 31.

Adding to 140111214031435 its reverse (534130412111041), we get a palindrome (674241626142476).

The spelling of 140111214031435 in words is "one hundred forty trillion, one hundred eleven billion, two hundred fourteen million, thirty-one thousand, four hundred thirty-five".

Divisors: 1 5 12613 63065 2221695299 11108476495 28022242806287 140111214031435