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14011220043 = 3219122935593
BaseRepresentation
bin11010000110010001…
…00100000001001011
31100011110120201120200
431003020210001023
5212143333020133
610234153023243
71004132256012
oct150310440113
940143521520
1014011220043
115a3aa71aa7
1228703b4b23
131423a39b62
1496cb97a79
155700ec913
hex34322404b

14011220043 has 24 divisors (see below), whose sum is σ = 20433803520. Its totient is φ = 9251072640.

The previous prime is 14011220011. The next prime is 14011220077. The reversal of 14011220043 is 34002211041.

14011220043 is a `hidden beast` number, since 1 + 401 + 1 + 220 + 0 + 43 = 666.

It is not a de Polignac number, because 14011220043 - 25 = 14011220011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14011219998 and 14011220025.

It is not an unprimeable number, because it can be changed into a prime (14011221043) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 375855 + ... + 411447.

It is an arithmetic number, because the mean of its divisors is an integer number (851408480).

Almost surely, 214011220043 is an apocalyptic number.

14011220043 is a deficient number, since it is larger than the sum of its proper divisors (6422583477).

14011220043 is a wasteful number, since it uses less digits than its factorization.

14011220043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36019 (or 36016 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 18.

Adding to 14011220043 its reverse (34002211041), we get a palindrome (48013431084).

The spelling of 14011220043 in words is "fourteen billion, eleven million, two hundred twenty thousand, forty-three".

Divisors: 1 3 9 191 229 573 687 1719 2061 35593 43739 106779 131217 320337 393651 6798263 8150797 20394789 24452391 61184367 73357173 1556802227 4670406681 14011220043