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14011220042 = 27005610021
BaseRepresentation
bin11010000110010001…
…00100000001001010
31100011110120201120122
431003020210001022
5212143333020132
610234153023242
71004132256011
oct150310440112
940143521518
1014011220042
115a3aa71aa6
1228703b4b22
131423a39b61
1496cb97a78
155700ec912
hex34322404a

14011220042 has 4 divisors (see below), whose sum is σ = 21016830066. Its totient is φ = 7005610020.

The previous prime is 14011220011. The next prime is 14011220077. The reversal of 14011220042 is 24002211041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 24002211041 = 87323274867.

It can be written as a sum of positive squares in only one way, i.e., 13950208321 + 61011721 = 118111^2 + 7811^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 14011220042.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3502805009 + ... + 3502805012.

Almost surely, 214011220042 is an apocalyptic number.

14011220042 is a deficient number, since it is larger than the sum of its proper divisors (7005610024).

14011220042 is an equidigital number, since it uses as much as digits as its factorization.

14011220042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7005610023.

The product of its (nonzero) digits is 128, while the sum is 17.

Adding to 14011220042 its reverse (24002211041), we get a palindrome (38013431083).

Subtracting 14011220042 from its reverse (24002211041), we obtain a palindrome (9990990999).

The spelling of 14011220042 in words is "fourteen billion, eleven million, two hundred twenty thousand, forty-two".

Divisors: 1 2 7005610021 14011220042