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14011242024347 is a prime number
BaseRepresentation
bin1100101111100011111100…
…0110101000110110011011
31211121110110112202221222122
43023320333012220312123
53314030010424234342
645444401542411455
72644164432106541
oct313707706506633
954543415687878
1014011242024347
1145121529399a7
1216a3580730b8b
137a834005a969
1436620d53dd91
151946e7d484d2
hexcbe3f1a8d9b

14011242024347 has 2 divisors, whose sum is σ = 14011242024348. Its totient is φ = 14011242024346.

The previous prime is 14011242024331. The next prime is 14011242024349. The reversal of 14011242024347 is 74342024211041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14011242024347 - 24 = 14011242024331 is a prime.

Together with 14011242024349, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14011242024349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7005621012173 + 7005621012174.

It is an arithmetic number, because the mean of its divisors is an integer number (7005621012174).

Almost surely, 214011242024347 is an apocalyptic number.

14011242024347 is a deficient number, since it is larger than the sum of its proper divisors (1).

14011242024347 is an equidigital number, since it uses as much as digits as its factorization.

14011242024347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43008, while the sum is 35.

Adding to 14011242024347 its reverse (74342024211041), we get a palindrome (88353266235388).

The spelling of 14011242024347 in words is "fourteen trillion, eleven billion, two hundred forty-two million, twenty-four thousand, three hundred forty-seven".