140113 has 4 divisors (see below), whose sum is σ = 141120. Its totient is φ = 139108.

The previous prime is 140111. The next prime is 140123. The reversal of 140113 is 311041.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 140113 - 2¹ = 140111 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140113.

It is not an unprimeable number, because it can be changed into a prime (140111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253 + ... + 586.

It is an arithmetic number, because the mean of its divisors is an integer number (35280).

2¹⁴⁰¹¹³ is an apocalyptic number.

It is an amenable number.

140113 is a deficient number, since it is larger than the sum of its proper divisors (1007).

140113 is an equidigital number, since it uses as much as digits as its factorization.

140113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1006.

The product of its (nonzero) digits is 12, while the sum is 10.

The square root of 140113 is about 374.3167108212. The cubic root of 140113 is about 51.9389075433.

Adding to 140113 its reverse (311041), we get a palindrome (451154).

It can be divided in two parts, 140 and 113, that added together give a triangular number (253 = T₂₂).

The spelling of 140113 in words is "one hundred forty thousand, one hundred thirteen".