Base | Representation |
---|---|
bin | 11111110110111010100010… |
… | …001011110000011100100100 |
3 | 200101002200111220212102022210 |
4 | 133312322202023300130210 |
5 | 121331103204343333444 |
6 | 1213555031222123420 |
7 | 41340561220325316 |
oct | 3766724213603444 |
9 | 611080456772283 |
10 | 140113144121124 |
11 | 4070a718129069 |
12 | 1386aa48580570 |
13 | 60247c7412bb5 |
14 | 2685725cb17b6 |
15 | 112e9e76457b9 |
hex | 7f6ea22f0724 |
140113144121124 has 48 divisors (see below), whose sum is σ = 327077385155136. Its totient is φ = 46683423158400.
The previous prime is 140113144121113. The next prime is 140113144121143. The reversal of 140113144121124 is 421121441311041.
It is a junction number, because it is equal to n+sod(n) for n = 140113144121091 and 140113144121100.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1776310374 + ... + 1776389250.
It is an arithmetic number, because the mean of its divisors is an integer number (6814112190732).
Almost surely, 2140113144121124 is an apocalyptic number.
It is an amenable number.
140113144121124 is an abundant number, since it is smaller than the sum of its proper divisors (186964241034012).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
140113144121124 is a wasteful number, since it uses less digits than its factorization.
140113144121124 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143436 (or 143434 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 30.
Adding to 140113144121124 its reverse (421121441311041), we get a palindrome (561234585432165).
The spelling of 140113144121124 in words is "one hundred forty trillion, one hundred thirteen billion, one hundred forty-four million, one hundred twenty-one thousand, one hundred twenty-four".
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