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14011314412203 = 3218150591700173
BaseRepresentation
bin1100101111100100001101…
…1010110001101010101011
31211121110122120222122110100
43023321003122301222223
53314030132442142303
645444413050120443
72644166301310053
oct313710332615253
954543576878410
1014011314412203
11451218a790a79
1216a35a0a20123
137a8352054304
14366218dc4563
151946ee3968a3
hexcbe436b1aab

14011314412203 has 24 divisors (see below), whose sum is σ = 20354415121040. Its totient is φ = 9287427574080.

The previous prime is 14011314412201. The next prime is 14011314412253. The reversal of 14011314412203 is 30221441311041.

It is a happy number.

14011314412203 is a `hidden beast` number, since 1 + 4 + 0 + 1 + 13 + 1 + 441 + 2 + 203 = 666.

It is not a de Polignac number, because 14011314412203 - 21 = 14011314412201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14011314412201) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7391025 + ... + 9091197.

Almost surely, 214011314412203 is an apocalyptic number.

14011314412203 is a deficient number, since it is larger than the sum of its proper divisors (6343100708837).

14011314412203 is a wasteful number, since it uses less digits than its factorization.

14011314412203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1705419 (or 1705416 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 14011314412203 its reverse (30221441311041), we get a palindrome (44232755723244).

The spelling of 14011314412203 in words is "fourteen trillion, eleven billion, three hundred fourteen million, four hundred twelve thousand, two hundred three".

Divisors: 1 3 9 181 543 1629 5059 15177 45531 915679 1700173 2747037 5100519 8241111 15301557 307731313 923193939 2769581817 8601175207 25803525621 77410576863 1556812712467 4670438137401 14011314412203