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14011323042103 = 67233389637473
BaseRepresentation
bin1100101111100100001111…
…1011101100100100110111
31211121110200012020002110021
43023321003323230210313
53314030142144321403
645444413555110011
72644166434542112
oct313710373544467
954543605202407
1014011323042103
114512194645822
1216a35a38a2307
137a8353a8636a
1436621a1cd579
151946eeeed8bd
hexcbe43eec937

14011323042103 has 8 divisors (see below), whose sum is σ = 14226542773488. Its totient is φ = 13796282590464.

The previous prime is 14011323042007. The next prime is 14011323042163. The reversal of 14011323042103 is 30124032311041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14011323042103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011323042163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 44662426 + ... + 44975047.

It is an arithmetic number, because the mean of its divisors is an integer number (1778317846686).

Almost surely, 214011323042103 is an apocalyptic number.

14011323042103 is a deficient number, since it is larger than the sum of its proper divisors (215219731385).

14011323042103 is an equidigital number, since it uses as much as digits as its factorization.

14011323042103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 89639873.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 14011323042103 its reverse (30124032311041), we get a palindrome (44135355353144).

The spelling of 14011323042103 in words is "fourteen trillion, eleven billion, three hundred twenty-three million, forty-two thousand, one hundred three".

Divisors: 1 67 2333 156311 89637473 6005710691 209124224509 14011323042103