14011334013 has 4 divisors (see below), whose sum is σ = 18681778688. Its totient is φ = 9340889340.

The previous prime is 14011333969. The next prime is 14011334017. The reversal of 14011334013 is 31043311041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31043311041 = 3 ⋅10347770347.

It is not a de Polignac number, because 14011334013 - 2⁶ = 14011333949 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14011334017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335222333 + ... + 2335222338.

It is an arithmetic number, because the mean of its divisors is an integer number (4670444672).

Almost surely, 2^14011334013 is an apocalyptic number.

It is an amenable number.

14011334013 is a deficient number, since it is larger than the sum of its proper divisors (4670444675).

14011334013 is an equidigital number, since it uses as much as digits as its factorization.

14011334013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4670444674.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 14011334013 its reverse (31043311041), we get a palindrome (45054645054).

The spelling of 14011334013 in words is "fourteen billion, eleven million, three hundred thirty-four thousand, thirteen".