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14011344323 = 47298113709
BaseRepresentation
bin11010000110010010…
…00010010111000011
31100011110211001001122
431003021002113003
5212143401004243
610234155422455
71004133314234
oct150311022703
940143731048
1014011344323
115a40047409
122870454a2b
131423a815b2
1496cbcb08b
15570124668
hex3432425c3

14011344323 has 4 divisors (see below), whose sum is σ = 14309458080. Its totient is φ = 13713230568.

The previous prime is 14011344293. The next prime is 14011344341. The reversal of 14011344323 is 32344311041.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14011344323 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14011344292 and 14011344301.

It is not an unprimeable number, because it can be changed into a prime (14011344343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 149056808 + ... + 149056901.

It is an arithmetic number, because the mean of its divisors is an integer number (3577364520).

Almost surely, 214011344323 is an apocalyptic number.

14011344323 is a deficient number, since it is larger than the sum of its proper divisors (298113757).

14011344323 is an equidigital number, since it uses as much as digits as its factorization.

14011344323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 298113756.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 14011344323 its reverse (32344311041), we get a palindrome (46355655364).

The spelling of 14011344323 in words is "fourteen billion, eleven million, three hundred forty-four thousand, three hundred twenty-three".

Divisors: 1 47 298113709 14011344323