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14012004310041 = 310146244238647
BaseRepresentation
bin1100101111100110110010…
…0010100001110000011001
31211121112102200011002101010
43023321230202201300121
53314033041100410131
645445005333044133
72644222346325033
oct313715442416031
954545380132333
1014012004310041
114512504160481
1216a3753a86649
137a8431c6749a
1436628288cc53
1519473ec20b46
hexcbe6c8a1c19

14012004310041 has 8 divisors (see below), whose sum is σ = 18867649368384. Its totient is φ = 9248847729200.

The previous prime is 14012004310039. The next prime is 14012004310061. The reversal of 14012004310041 is 14001340021041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14012004310041 - 21 = 14012004310039 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14012004310021) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23122119021 + ... + 23122119626.

It is an arithmetic number, because the mean of its divisors is an integer number (2358456171048).

Almost surely, 214012004310041 is an apocalyptic number.

It is an amenable number.

14012004310041 is a deficient number, since it is larger than the sum of its proper divisors (4855645058343).

14012004310041 is a wasteful number, since it uses less digits than its factorization.

14012004310041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 46244238751.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 14012004310041 its reverse (14001340021041), we get a palindrome (28013344331082).

The spelling of 14012004310041 in words is "fourteen trillion, twelve billion, four million, three hundred ten thousand, forty-one".

Divisors: 1 3 101 303 46244238647 138732715941 4670668103347 14012004310041