14012004341317 has 2 divisors, whose sum is σ = 14012004341318. Its totient is φ = 14012004341316.

The previous prime is 14012004341299. The next prime is 14012004341417. The reversal of 14012004341317 is 71314340021041.

14012004341317 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13575989762721 + 436014578596 = 3684561^2 + 660314^2 .

It is a cyclic number.

It is not a de Polignac number, because 14012004341317 - 2⁷ = 14012004341189 is a prime.

It is a super-3 number, since 3×14012004341317³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14012004341417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006002170658 + 7006002170659.

It is an arithmetic number, because the mean of its divisors is an integer number (7006002170659).

Almost surely, 2^{14012004341317} is an apocalyptic number.

It is an amenable number.

14012004341317 is a deficient number, since it is larger than the sum of its proper divisors (1).

14012004341317 is an equidigital number, since it uses as much as digits as its factorization.

14012004341317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 31.

Adding to 14012004341317 its reverse (71314340021041), we get a palindrome (85326344362358).

The spelling of 14012004341317 in words is "fourteen trillion, twelve billion, four million, three hundred forty-one thousand, three hundred seventeen".