14012043423133 has 4 divisors (see below), whose sum is σ = 16013763912160. Its totient is φ = 12010322934108.

The previous prime is 14012043423113. The next prime is 14012043423139. The reversal of 14012043423133 is 33132434021041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14012043423133 - 2¹⁷ = 14012043292061 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14012043423095 and 14012043423104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14012043423139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1000860244503 + ... + 1000860244516.

It is an arithmetic number, because the mean of its divisors is an integer number (4003440978040).

Almost surely, 2^{14012043423133} is an apocalyptic number.

It is an amenable number.

14012043423133 is a deficient number, since it is larger than the sum of its proper divisors (2001720489027).

14012043423133 is an equidigital number, since it uses as much as digits as its factorization.

14012043423133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2001720489026.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 14012043423133 its reverse (33132434021041), we get a palindrome (47144477444174).

The spelling of 14012043423133 in words is "fourteen trillion, twelve billion, forty-three million, four hundred twenty-three thousand, one hundred thirty-three".