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140121045000355 = 5139201613014389
BaseRepresentation
bin11111110111000001111001…
…000111001110000010100011
3200101010102220112202200002111
4133313001321013032002203
5121331220400010002410
61214002415221300151
741341261055564536
oct3767017107160243
9611112815680074
10140121045000355
1140713001a55621
1213870492564657
13602548625c773
142685c75336a1d
15112ed0b0b1b8a
hex7f70791ce0a3

140121045000355 has 8 divisors (see below), whose sum is σ = 169354932087600. Its totient is φ = 111290383942176.

The previous prime is 140121045000331. The next prime is 140121045000407. The reversal of 140121045000355 is 553000540121041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140121045000355 - 213 = 140121044992163 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100806506500 + ... + 100806507889.

It is an arithmetic number, because the mean of its divisors is an integer number (21169366510950).

Almost surely, 2140121045000355 is an apocalyptic number.

140121045000355 is a deficient number, since it is larger than the sum of its proper divisors (29233887087245).

140121045000355 is a wasteful number, since it uses less digits than its factorization.

140121045000355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 201613014533.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 140121045000355 its reverse (553000540121041), we get a palindrome (693121585121396).

The spelling of 140121045000355 in words is "one hundred forty trillion, one hundred twenty-one billion, forty-five million, three hundred fifty-five", and thus it is an aban number.

Divisors: 1 5 139 695 201613014389 1008065071945 28024209000071 140121045000355