Base | Representation |
---|---|
bin | 10100011000111110110… |
… | …000011001010001010011 |
3 | 11221221202212222120010222 |
4 | 110120332300121101103 |
5 | 140424140311243212 |
6 | 2551412532343255 |
7 | 203143226200505 |
oct | 24307660312123 |
9 | 4857685876128 |
10 | 1401212212307 |
11 | 4a0283845346 |
12 | 1a7693174b2b |
13 | a2197ab5b6b |
14 | 4bb675d7d75 |
15 | 266ae7adc72 |
hex | 1463ec19453 |
1401212212307 has 2 divisors, whose sum is σ = 1401212212308. Its totient is φ = 1401212212306.
The previous prime is 1401212212157. The next prime is 1401212212319. The reversal of 1401212212307 is 7032122121041.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1401212212307 - 212 = 1401212208211 is a prime.
It is not a weakly prime, because it can be changed into another prime (1401212212397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700606106153 + 700606106154.
It is an arithmetic number, because the mean of its divisors is an integer number (700606106154).
Almost surely, 21401212212307 is an apocalyptic number.
1401212212307 is a deficient number, since it is larger than the sum of its proper divisors (1).
1401212212307 is an equidigital number, since it uses as much as digits as its factorization.
1401212212307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 1401212212307 its reverse (7032122121041), we get a palindrome (8433334333348).
The spelling of 1401212212307 in words is "one trillion, four hundred one billion, two hundred twelve million, two hundred twelve thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •