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1401214114141 = 4297326091253
BaseRepresentation
bin10100011000111110110…
…111101001100101011101
311221221210000120011222021
4110120332313221211131
5140424141303123031
62551413041220141
7203143251311302
oct24307667514535
94857700504867
101401214114141
114a0284924206
121a7693931651
13a21983006ca
144bb679710a9
15266aea37511
hex1463ede995d

1401214114141 has 4 divisors (see below), whose sum is σ = 1401540209692. Its totient is φ = 1400888018592.

The previous prime is 1401214114099. The next prime is 1401214114151. The reversal of 1401214114141 is 1414114121041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 851844086116 + 549370028025 = 922954^2 + 741195^2 .

It is a cyclic number.

It is not a de Polignac number, because 1401214114141 - 215 = 1401214081373 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1401214114151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163041330 + ... + 163049923.

It is an arithmetic number, because the mean of its divisors is an integer number (350385052423).

Almost surely, 21401214114141 is an apocalyptic number.

It is an amenable number.

1401214114141 is a deficient number, since it is larger than the sum of its proper divisors (326095551).

1401214114141 is an equidigital number, since it uses as much as digits as its factorization.

1401214114141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 326095550.

The product of its (nonzero) digits is 512, while the sum is 25.

Adding to 1401214114141 its reverse (1414114121041), we get a palindrome (2815328235182).

The spelling of 1401214114141 in words is "one trillion, four hundred one billion, two hundred fourteen million, one hundred fourteen thousand, one hundred forty-one".

Divisors: 1 4297 326091253 1401214114141